Forums: Climbing Information: Gear Heads:
Stretchy terminology
RSS FeedRSS Feeds for Gear Heads

Premier Sponsor:

 
First page Previous page 1 2 3 Next page Last page  View All


clc


Jun 3, 2010, 6:22 PM
Post #26 of 58 (5511 views)
Shortcut

Registered: Feb 12, 2005
Posts: 495

Re: [j_ung] Stretchy terminology [In reply to]
Report this Post
Average: avg_1 avg_2 avg_3 avg_4 avg_5 (0 ratings)  
Can't Post

Jay kept it simple up near the top of this post.


desertwanderer81


Jun 3, 2010, 6:32 PM
Post #27 of 58 (5503 views)
Shortcut

Registered: Sep 5, 2007
Posts: 2272

Re: [clews] Stretchy terminology [In reply to]
Report this Post
Average: avg_1 avg_2 avg_3 avg_4 avg_5 (0 ratings)  
Can't Post

clews wrote:
ptlong wrote:
clews wrote:
The rope is critically damped

clews wrote:
the heat created by the rope when it stretches does nothing to stop your fall

These two statements are contradictory.

Must I point out that after you fall and the rope catches you you start swing? Only after you stop yourself against the rock do you stop moving... there we go, the source of this magical critical damping

Sure there is some damping in the rope but most of it comes from friction between rope, quickdraws, and you hitting the rock

Clews is more correct than most others here.

Most of the energy goes into a number of places. Bouncing around after the fall, elongating the spring of the rope, permanetly deformation of the core of the rope, and the friction between the rope and the carabiners/rock (especially the carabiner that is actually catching you).

Let's say for one moment we look at the top most carabiner. Let's assume that you hit 8kN of force during a decent fall and the sliding coefficient of friction for the rope's sheath and the aluminium is .2.

At this moment, that carabiner would be resisting with 1.6 kN of force. This is equal to a 360 lbs of dampaning force. This is why you do not bounce a LOT when you fall on a climbing rope. There is a ton of friction in your system.

The internal friction in the rope itself absorbs very little of the actual energy of a fall.


Scooter12ga


Jun 3, 2010, 6:57 PM
Post #28 of 58 (5489 views)
Shortcut

Registered: May 6, 2008
Posts: 65

Re: [desertwanderer81] Stretchy terminology [In reply to]
Report this Post
Average: avg_1 avg_2 avg_3 avg_4 avg_5 (0 ratings)  
Can't Post

Haven't seen this mentioned yet so I figure I'll add some fuel to the fire:

The potential energy stored in the stretch of the rope is converted into work when it recoils:

1. It takes some weight off of you when climbing back up the route.

0r

2. It shortens after you and your partner lower to the ground.


clews


Jun 3, 2010, 7:07 PM
Post #29 of 58 (5480 views)
Shortcut

Registered: Nov 10, 2008
Posts: 190

Re: [desertwanderer81] Stretchy terminology [In reply to]
Report this Post
Average: avg_1 avg_2 avg_3 avg_4 avg_5 (1 rating)  
Can't Post

desertwanderer81 wrote:
clews wrote:
ptlong wrote:
clews wrote:
The rope is critically damped

clews wrote:
the heat created by the rope when it stretches does nothing to stop your fall

These two statements are contradictory.

Must I point out that after you fall and the rope catches you you start swing? Only after you stop yourself against the rock do you stop moving... there we go, the source of this magical critical damping

Sure there is some damping in the rope but most of it comes from friction between rope, quickdraws, and you hitting the rock

Clews is more correct than most others here.

Most of the energy goes into a number of places. Bouncing around after the fall, elongating the spring of the rope, permanetly deformation of the core of the rope, and the friction between the rope and the carabiners/rock (especially the carabiner that is actually catching you).

Let's say for one moment we look at the top most carabiner. Let's assume that you hit 8kN of force during a decent fall and the sliding coefficient of friction for the rope's sheath and the aluminium is .2.

At this moment, that carabiner would be resisting with 1.6 kN of force. This is equal to a 360 lbs of dampaning force. This is why you do not bounce a LOT when you fall on a climbing rope. There is a ton of friction in your system.

The internal friction in the rope itself absorbs very little of the actual energy of a fall.

we have a winner folks


ptlong


Jun 3, 2010, 7:08 PM
Post #30 of 58 (5477 views)
Shortcut

Registered: Oct 4, 2007
Posts: 418

Re: [desertwanderer81] Stretchy terminology [In reply to]
Report this Post
Average: avg_1 avg_2 avg_3 avg_4 avg_5 (0 ratings)  
Can't Post

desertwanderer81 wrote:
Most of the energy goes into a number of places. Bouncing around after the fall, elongating the spring of the rope, permanetly deformation of the core of the rope, and the friction between the rope and the carabiners/rock (especially the carabiner that is actually catching you).

Let's say for one moment we look at the top most carabiner. Let's assume that you hit 8kN of force during a decent fall and the sliding coefficient of friction for the rope's sheath and the aluminium is .2.

At this moment, that carabiner would be resisting with 1.6 kN of force. This is equal to a 360 lbs of dampaning force. This is why you do not bounce a LOT when you fall on a climbing rope. There is a ton of friction in your system.

The internal friction in the rope itself absorbs very little of the actual energy of a fall.

In a UIAA drop test there is very little rope that slides over the top carabiner. And yet damping is still observed in the system, with roughly half the energy dissipated with each bounce (including the first).

Jay is right that the rope absorbs energy, not force. But he is wrong in suggesting that nearly all of it is in the form of strain energy.


[edited for brevity]


(This post was edited by ptlong on Jun 3, 2010, 8:21 PM)


rmsusa


Jun 3, 2010, 7:46 PM
Post #31 of 58 (5453 views)
Shortcut

Registered: May 24, 2004
Posts: 1017

Re: [jt512] Stretchy terminology [In reply to]
Report this Post
Average: avg_1 avg_2 avg_3 avg_4 avg_5 (0 ratings)  
Can't Post

In reply to:
So, kinetic energy has been converted to strain energy

What's the difference between stress and strain?


clews


Jun 3, 2010, 8:29 PM
Post #32 of 58 (5425 views)
Shortcut

Registered: Nov 10, 2008
Posts: 190

Re: [rmsusa] Stretchy terminology [In reply to]
Report this Post
Average: avg_1 avg_2 avg_3 avg_4 avg_5 (0 ratings)  
Can't Post

stress is pressure force/area

strain is displacement/length (mm/mm)

edit to add: strain is like saying a 1m rope stretches 1mm then the strain is 0.001mm/mm


(This post was edited by clews on Jun 3, 2010, 8:31 PM)


desertwanderer81


Jun 3, 2010, 8:29 PM
Post #33 of 58 (5423 views)
Shortcut

Registered: Sep 5, 2007
Posts: 2272

Re: [ptlong] Stretchy terminology [In reply to]
Report this Post
Average: avg_1 avg_2 avg_3 avg_4 avg_5 (0 ratings)  
Can't Post

ptlong wrote:
desertwanderer81 wrote:
Most of the energy goes into a number of places. Bouncing around after the fall, elongating the spring of the rope, permanetly deformation of the core of the rope, and the friction between the rope and the carabiners/rock (especially the carabiner that is actually catching you).

Let's say for one moment we look at the top most carabiner. Let's assume that you hit 8kN of force during a decent fall and the sliding coefficient of friction for the rope's sheath and the aluminium is .2.

At this moment, that carabiner would be resisting with 1.6 kN of force. This is equal to a 360 lbs of dampaning force. This is why you do not bounce a LOT when you fall on a climbing rope. There is a ton of friction in your system.

The internal friction in the rope itself absorbs very little of the actual energy of a fall.

Jay Tanzman has fleshed out a model for ropes that includes the friction in the top carabiner. We can calculate this frictional energy, based on Jay's model, and compare it to the fall energy, for a UIAA drop test.

Let's start with a real rope, say, the Blue Water Lightning Pro 9.7mm. It has a maximum impact force of 7.8 kN and a dynamic elongation of 32.2%.

Using Jay's model, and assuming a frictional coefficient of 0.33, we can calculate the rope modulus and from that determine the rope elongation and the carabiner frictional energy.

According to this model, the energy dissipated by the carabiner is 0.12 kJ, less than 3% of the fall energy.

Or course Jay's model isn't accurate. It overestimates the elongation of the rope by nearly 40%. But it doesn't come close to suggesting that the top carabiner is responsible for very much of the fall energy.

Jay's primary contention is that at the bottom of the fall virtually all of the energy is in the form of strain energy. But if you calculate this energy based on his model it accounts for only about 52% of the fall energy. Even adding in the 3% frictional loss due to the carabiner leaves a large amount of energy unaccounted for.

So the simple answer that Jay Young was apparently looking for is that the rope absorbs energy, not force. But it doesn't simply convert it to strain energy like a simple spring model suggests.

So, what you need to do is design an aparatus where you can do various drop tests of masses/drop heights that have energies that do not cause the rope to elongate past its elastic limit.

Then use masses which greatly excede the elastic portion of the stress strain curve and push it into the plastic portion.

Observe the velocity/position with a high speed camera and the forces with a meter.

Do this drop with the rope connected directly to an anchor. Then do the same drop height/weight and rope length with a carabiner absorbing the forces.

You should be able to come up with some decent formulas which predict the energy absorbed by the rope.

And don't forget, the energy absorbed by the plastic deformation in the rope is rather large too. Separating the energy absorbed by plastic deformation and internal friction is very difficult without embeded temperature sensors, etc.

Also, do not forget that the rope itself is not a homogenous body which behaves according to a simple spring/harmonics equation. Under the most simple modeling to even remotely accurately model the situation, you would need essentially THREE separate equations to model the different elements of the rope.

You start to get into a really neat/interesting differential equation at that point :)


clews


Jun 3, 2010, 8:37 PM
Post #34 of 58 (5414 views)
Shortcut

Registered: Nov 10, 2008
Posts: 190

Re: [desertwanderer81] Stretchy terminology [In reply to]
Report this Post
Average: avg_1 avg_2 avg_3 avg_4 avg_5 (0 ratings)  
Can't Post

desertwanderer81 wrote:
ptlong wrote:
desertwanderer81 wrote:
Most of the energy goes into a number of places. Bouncing around after the fall, elongating the spring of the rope, permanetly deformation of the core of the rope, and the friction between the rope and the carabiners/rock (especially the carabiner that is actually catching you).

Let's say for one moment we look at the top most carabiner. Let's assume that you hit 8kN of force during a decent fall and the sliding coefficient of friction for the rope's sheath and the aluminium is .2.

At this moment, that carabiner would be resisting with 1.6 kN of force. This is equal to a 360 lbs of dampaning force. This is why you do not bounce a LOT when you fall on a climbing rope. There is a ton of friction in your system.

The internal friction in the rope itself absorbs very little of the actual energy of a fall.

Jay Tanzman has fleshed out a model for ropes that includes the friction in the top carabiner. We can calculate this frictional energy, based on Jay's model, and compare it to the fall energy, for a UIAA drop test.

Let's start with a real rope, say, the Blue Water Lightning Pro 9.7mm. It has a maximum impact force of 7.8 kN and a dynamic elongation of 32.2%.

Using Jay's model, and assuming a frictional coefficient of 0.33, we can calculate the rope modulus and from that determine the rope elongation and the carabiner frictional energy.

According to this model, the energy dissipated by the carabiner is 0.12 kJ, less than 3% of the fall energy.

Or course Jay's model isn't accurate. It overestimates the elongation of the rope by nearly 40%. But it doesn't come close to suggesting that the top carabiner is responsible for very much of the fall energy.

Jay's primary contention is that at the bottom of the fall virtually all of the energy is in the form of strain energy. But if you calculate this energy based on his model it accounts for only about 52% of the fall energy. Even adding in the 3% frictional loss due to the carabiner leaves a large amount of energy unaccounted for.

So the simple answer that Jay Young was apparently looking for is that the rope absorbs energy, not force. But it doesn't simply convert it to strain energy like a simple spring model suggests.

So, what you need to do is design an aparatus where you can do various drop tests of masses/drop heights that have energies that do not cause the rope to elongate past its elastic limit.

Then use masses which greatly excede the elastic portion of the stress strain curve and push it into the plastic portion.

Observe the velocity/position with a high speed camera and the forces with a meter.

Do this drop with the rope connected directly to an anchor. Then do the same drop height/weight and rope length with a carabiner absorbing the forces.

You should be able to come up with some decent formulas which predict the energy absorbed by the rope.

And don't forget, the energy absorbed by the plastic deformation in the rope is rather large too. Separating the energy absorbed by plastic deformation and internal friction is very difficult without embeded temperature sensors, etc.

Also, do not forget that the rope itself is not a homogenous body which behaves according to a simple spring/harmonics equation. Under the most simple modeling to even remotely accurately model the situation, you would need essentially THREE separate equations to model the different elements of the rope.

You start to get into a really neat/interesting differential equation at that point :)

I knew you had to be a civil engineer before I even looked at your profileCool


desertwanderer81


Jun 3, 2010, 8:48 PM
Post #35 of 58 (5401 views)
Shortcut

Registered: Sep 5, 2007
Posts: 2272

Re: [clews] Stretchy terminology [In reply to]
Report this Post
Average: avg_1 avg_2 avg_3 avg_4 avg_5 (0 ratings)  
Can't Post

Heh, practicing for 6 years and currently a grad student on the side. I do a lot of work with polymer materials so I am fairly familiar with what is going on inside.

There is a lot of "stuff" going on inside and to model it all, you'd have to have a VERY long equation. Modeling the tragectory of a rocket to another planetary body is actually much more simple.


desertwanderer81


Jun 3, 2010, 8:52 PM
Post #36 of 58 (5397 views)
Shortcut

Registered: Sep 5, 2007
Posts: 2272

Re: [ptlong] Stretchy terminology [In reply to]
Report this Post
Average: avg_1 avg_2 avg_3 avg_4 avg_5 (0 ratings)  
Can't Post

ptlong wrote:
desertwanderer81 wrote:
Most of the energy goes into a number of places. Bouncing around after the fall, elongating the spring of the rope, permanetly deformation of the core of the rope, and the friction between the rope and the carabiners/rock (especially the carabiner that is actually catching you).

Let's say for one moment we look at the top most carabiner. Let's assume that you hit 8kN of force during a decent fall and the sliding coefficient of friction for the rope's sheath and the aluminium is .2.

At this moment, that carabiner would be resisting with 1.6 kN of force. This is equal to a 360 lbs of dampaning force. This is why you do not bounce a LOT when you fall on a climbing rope. There is a ton of friction in your system.

The internal friction in the rope itself absorbs very little of the actual energy of a fall.

In a UIAA drop test there is very little rope that slides over the top carabiner. And yet damping is still observed in the system, with roughly half the energy dissipated with each bounce (including the first).

Jay is right that the rope absorbs energy, not force. But he is wrong in suggesting that nearly all of it is in the form of strain energy.


[edited for brevity]

Wait, what? Very little rope that "slides over the top carabiner"? Is the rope fixed to a point on top or is it running through a carabiner? If it is running through a carabiner, it does not matter "how much" is actually running over it or not. The friction is calculated based on the normal force, not the surface area.


ptlong


Jun 3, 2010, 9:01 PM
Post #37 of 58 (5393 views)
Shortcut

Registered: Oct 4, 2007
Posts: 418

Re: [desertwanderer81] Stretchy terminology [In reply to]
Report this Post
Average: avg_1 avg_2 avg_3 avg_4 avg_5 (0 ratings)  
Can't Post

desertwanderer81 wrote:
And don't forget, the energy absorbed by the plastic deformation in the rope is rather large too. Separating the energy absorbed by plastic deformation and internal friction is very difficult without embeded temperature sensors, etc.

You're making a distinction that I wasn't bothering with, namely between plastic deformation (which generally involves the release of a lot of heat) and "internal friction". My point was that strain energy and carabiner frictional loss cannot fully account for the fall energy. Rope damping, whatever the exact mechanism, is quite significant. No need for fancy experiments, the evidence is readily available.


ptlong


Jun 3, 2010, 9:06 PM
Post #38 of 58 (5388 views)
Shortcut

Registered: Oct 4, 2007
Posts: 418

Re: [desertwanderer81] Stretchy terminology [In reply to]
Report this Post
Average: avg_1 avg_2 avg_3 avg_4 avg_5 (0 ratings)  
Can't Post

desertwanderer81 wrote:
Wait, what? Very little rope that "slides over the top carabiner"? Is the rope fixed to a point on top or is it running through a carabiner? If it is running through a carabiner, it does not matter "how much" is actually running over it or not. The friction is calculated based on the normal force, not the surface area.

We're talking about frictional ENERGY loss, not just the force. In a high fall factor drop very little rope slips over the carabiner and the frictional loss is relatively small.


desertwanderer81


Jun 3, 2010, 9:12 PM
Post #39 of 58 (5381 views)
Shortcut

Registered: Sep 5, 2007
Posts: 2272

Re: [ptlong] Stretchy terminology [In reply to]
Report this Post
Average: avg_1 avg_2 avg_3 avg_4 avg_5 (0 ratings)  
Can't Post

ptlong wrote:
desertwanderer81 wrote:
And don't forget, the energy absorbed by the plastic deformation in the rope is rather large too. Separating the energy absorbed by plastic deformation and internal friction is very difficult without embeded temperature sensors, etc.

You're making a distinction that I wasn't bothering with, namely between plastic deformation (which generally involves the release of a lot of heat) and "internal friction". My point was that strain energy and carabiner frictional loss cannot fully account for the fall energy. Rope damping, whatever the exact mechanism, is quite significant. No need for fancy experiments, the evidence is readily available.

The distinction however is huge. Especially when we're talking about the energy involved :p


desertwanderer81


Jun 3, 2010, 9:18 PM
Post #40 of 58 (5370 views)
Shortcut

Registered: Sep 5, 2007
Posts: 2272

Re: [ptlong] Stretchy terminology [In reply to]
Report this Post
Average: avg_1 avg_2 avg_3 avg_4 avg_5 (0 ratings)  
Can't Post

ptlong wrote:
desertwanderer81 wrote:
Wait, what? Very little rope that "slides over the top carabiner"? Is the rope fixed to a point on top or is it running through a carabiner? If it is running through a carabiner, it does not matter "how much" is actually running over it or not. The friction is calculated based on the normal force, not the surface area.

We're talking about frictional ENERGY loss, not just the force. In a high fall factor drop very little rope slips over the carabiner and the frictional loss is relatively small.

Ahh, I misread what you wrote then. I thought you were talking about surface area, heh. What kind of length are we talking about here? Also, do you know what the sliding coefficient of friction between the rope and carabiner is?


ptlong


Jun 3, 2010, 9:23 PM
Post #41 of 58 (5369 views)
Shortcut

Registered: Oct 4, 2007
Posts: 418

Re: [desertwanderer81] Stretchy terminology [In reply to]
Report this Post
Average: avg_1 avg_2 avg_3 avg_4 avg_5 (0 ratings)  
Can't Post

desertwanderer81 wrote:
The distinction however is huge. Especially when we're talking about the energy involved :p

You just finished posting how you'd need a high speed camera and embedded temperature sensors to figure this out. Now you're so sure it's huge. Come on, you're shooting from the hip, admit it.

There is ample evidence that even in relatively low energy falls where plastic deformation is unimportnat the rope damping effect is large.


desertwanderer81


Jun 3, 2010, 9:29 PM
Post #42 of 58 (5356 views)
Shortcut

Registered: Sep 5, 2007
Posts: 2272

Re: [ptlong] Stretchy terminology [In reply to]
Report this Post
Average: avg_1 avg_2 avg_3 avg_4 avg_5 (0 ratings)  
Can't Post

Show the data and I'll believe it, hehe.


ptlong


Jun 3, 2010, 9:33 PM
Post #43 of 58 (5354 views)
Shortcut

Registered: Oct 4, 2007
Posts: 418

Re: [desertwanderer81] Stretchy terminology [In reply to]
Report this Post
Average: avg_1 avg_2 avg_3 avg_4 avg_5 (0 ratings)  
Can't Post

desertwanderer81 wrote:
Ahh, I misread what you wrote then. I thought you were talking about surface area, heh. What kind of length are we talking about here? Also, do you know what the sliding coefficient of friction between the rope and carabiner is?

UIAA drop test goes like this: 2.8 meters of rope, 5.0 meter fall. So there's 0.3 meters on the "belay" side, 2.5m on the "load" side.

Coefficient of friction? Something like 0.2-0.3, I think, depending on the metal, edge radius, rope, temperature, rope coating, etc.


(This post was edited by ptlong on Jun 3, 2010, 9:33 PM)


ptlong


Jun 3, 2010, 9:43 PM
Post #44 of 58 (5342 views)
Shortcut

Registered: Oct 4, 2007
Posts: 418

Re: [desertwanderer81] Stretchy terminology [In reply to]
Report this Post
Average: avg_1 avg_2 avg_3 avg_4 avg_5 (0 ratings)  
Can't Post

desertwanderer81 wrote:
Show the data and I'll believe it, hehe.

Martyn Pavier has data for you. He developed a model that agrees very well with experimental drop test data. His model does not rely upon plastic deformation, but merely springs and dashpots.

"Experimental and theoretical simulations of climbing falls"

link


hafilax


Jun 3, 2010, 10:28 PM
Post #45 of 58 (5328 views)
Shortcut

Registered: Dec 12, 2007
Posts: 3025

Re: [desertwanderer81] Stretchy terminology [In reply to]
Report this Post
Average: avg_1 avg_2 avg_3 avg_4 avg_5 (0 ratings)  
Can't Post

I've been playing with the Damped Harmonic Oscillator equation of motion this morning:
m y'' + d y' + k y =0
where m is the mass, d the damping coefficient and k is the spring constant. With boundary conditions y(t=0)=0 and y'(t=0)=v(t=0)=v0 (ie. spring engages at t=0 with initial velocity v0) you get something that looks like
y(t)=A*exp(-d/2m*t)*sin(w0*t)

By looking at y''(t) (which isn't pretty but is manageable) you can see the effect that the damping term has on the force on the mass. For small damping the peak force is at the minimum. As the damping approaches critical damping the peak force increases and instead of being where the mass velocity goes to 0 it moves to t=0. The force quickly takes off to high values very near critical damplng.

Looking at Pavier's paper on comparing a theoretical model for the rope and experiment it looks like the system is on the slightly under-damped side of things with the mass bouncing a bit.

All of this is to say that I don't think that the work done by the damping in the rope is insignificant. I wish that Pavier had done a comparison of his model to simpler models to show that his numerical approach is much better. It would have shown the modification to the expected peak force due to the damping of the rope.


ptlong


Jun 3, 2010, 10:49 PM
Post #46 of 58 (5318 views)
Shortcut

Registered: Oct 4, 2007
Posts: 418

Re: [hafilax] Stretchy terminology [In reply to]
Report this Post
Average: avg_1 avg_2 avg_3 avg_4 avg_5 (0 ratings)  
Can't Post

hafilax wrote:
All of this is to say that I don't think that the work done by the damping in the rope is insignificant. I wish that Pavier had done a comparison of his model to simpler models to show that his numerical approach is much better. It would have shown the modification to the expected peak force due to the damping of the rope.

One thing you will notice if you play with the simple spring model (Wexler) or a standard damped harmonic oscillator model is that you can't choose parameters that will allow your model to simultaneously reproduce the impact force and elongation values that are printed on your rope hangtag. You can select for either the same force or the same elongation, not both.

Here is a comparison of the Wexler and Pavier models, where same-force and same-elongation Wexler spring values are compared to the Pavier model. The same-force version actually looks pretty good... as long as you don't care about the elongation.




hafilax


Jun 3, 2010, 10:59 PM
Post #47 of 58 (5312 views)
Shortcut

Registered: Dec 12, 2007
Posts: 3025

Re: [ptlong] Stretchy terminology [In reply to]
Report this Post
Average: avg_1 avg_2 avg_3 avg_4 avg_5 (0 ratings)  
Can't Post

The Yowie Factor Laugh


patto


Jun 4, 2010, 12:31 AM
Post #48 of 58 (5285 views)
Shortcut

Registered: Nov 15, 2005
Posts: 1453

Re: [ptlong] Stretchy terminology [In reply to]
Report this Post
Average: avg_1 avg_2 avg_3 avg_4 avg_5 (0 ratings)  
Can't Post

I wonder if this posts was made purely to start a fight like the last thread. Laugh

In the interests of peace I think Jays post answers the original post the best. Angelic

That said:

ptlong wrote:
Jay is right that the rope absorbs energy, not force. But he is wrong in suggesting that nearly all of it is in the form of strain energy.

Agreed, while briefly it is true, that strain energy is quickly released in rebound and damped through many of the reasons mentioned. Some strain energy still remains as te rope is still longer but it is extremely minor.


jt512


Jun 4, 2010, 1:04 AM
Post #49 of 58 (5274 views)
Shortcut

Registered: Apr 12, 2001
Posts: 21904

Re: [j_ung] Stretchy terminology [In reply to]
Report this Post
Average: avg_1 avg_2 avg_3 avg_4 avg_5 (2 ratings)  
Can't Post

j_ung wrote:
jt512 wrote:
j_ung wrote:
I think we've established over and over again that "absorbs force," is technically incorrect to describe what happens when rope stretches during a fall. So, what exactly is the correct terminology to denote what a dynamic rope does? Is it "dissipate energy?" "Eat force and poop energy?"

The rope stretches, converting the kinetic energy of the falling climber into strain energy in the rope. So, saying that the rope "absorbs" energy (as opposed to force) is not too far off the mark.

The reason that a dynamic rope reduces the impact force on the climber, relative to a static rope (or the ground), is that force F is proportional to acceleration a:

F = ma ,

where m is mass (of the climber).

The stretchier the rope, the smaller will be a; and the smaller a is, the smaller F will be. A dynamic rope is stretchier than a static one; therefore, by the above argument, the impact force will be lower for a dynamic rope than a static one, all else equal.

Jay

That's pretty much what I was looking for.
J

I figured. Now that your question has been answered, you can sit back, relax, and watch the inevitable train wreck ensue.

Jay


(This post was edited by jt512 on Jun 4, 2010, 1:05 AM)


Partner j_ung


Jun 4, 2010, 12:16 PM
Post #50 of 58 (5295 views)
Shortcut

Registered: Nov 21, 2003
Posts: 18690

Re: [jt512] Stretchy terminology [In reply to]
Report this Post
Average: avg_1 avg_2 avg_3 avg_4 avg_5 (0 ratings)  
Can't Post

Freakin' engineers...

Laugh

First page Previous page 1 2 3 Next page Last page  View All

Forums : Climbing Information : Gear Heads

 


Search for (options)

Log In:

Username:
Password: Remember me:

Go Register
Go Lost Password?



Follow us on Twiter Become a Fan on Facebook